There are two possible reactions for cathode in the electrolysis of aqueous
\(ZnCl_2\) :\(Zn^{2+}\) (aq) + 2\(e^-\) → Zn(s) \(E^0\) = -0.76 V
2\(H_2\)O (l) + 2\(e^-\) → H2 (g) + 2\(OH^-\) (aq) \(E^0\) = - 0.83 V
Which one will take place? Why?
\(ZnCl_2\) :\(Zn^{2+}\) (aq) + 2\(e^-\) → Zn(s) \(E^0\) = -0.76 V
2\(H_2\)O (l) + 2\(e^-\) → H2 (g) + 2\(OH^-\) (aq) \(E^0\) = - 0.83 V
Which one will take place? Why?
\(Zn^{2+}\) is reduced to Zn preferentially at cathode because \(Zn^{2+}\) has higher reduction potential (-0.76V) than 2\(H_2\)O (- 0.83V)
Following reactions can occur at cathode during the electrolysis of aqueous silver nitrate solution using Pt electrodes:
Calculate emf of the following cell
Cd/\(Cd^{2+}\) (.10 M)//\(H_+\) (.20 M)/\(H_2\) (0.5 atm)/Pt
[Given E° for \(Cd^{2+}\) /Cd = -0.403V]
(a) Calculate G° for the reaction
Zn(s) + \(Cu^{2+}\)(aq) → \(Zn^{2+}\)(aq) + Cu(s)
Given: E° for \(Zn^{2+}\)/Zn = -0.76V and E° for \(Cu^{2+}\)/Cu = +0.34 V
R = 8.314 \(JK^{–1}\) \(mol^{–1}\), F = 96500 \(mol^{–1}\)
How many electrons flow when a current of 5 amps is passed through a solution for 193 sec ? Given F = 96500 C. \(N_0\) = 6.002 × \(10^{23}\) \(mol^{-1}\).
The conductivity of an aqueous solution of NaCl in a cell is 92 \(Ω^{−1}\) \(cm^{-1}\) the resistance offered by this cell is 247.8 Ω . Calculate the cell constant.
How is electrical conductance of a conductor related with length and area of cross-section of the conductor?
a. G = \(l. a.k^{-1}\)
b. G = \(k. l.a^{-1}\)
c. G = \(k.a. l^{-1}\)
d. G = \(k. l.a^{-2}\)
The electrical resistance of a column of 0.05 M KOH solution of diameter 1 cm and length 45.5 cm is 4.55 × 10³ ohm. Calculate its molar conductivity.
Define the following terms :
(i) Molar conductivity (),
(ii) Secondary batteries.
Calculate the molality of ethanol solution in which the mole fraction of water is 0.88.
There are two possible reactions for cathode in the electrolysis of aqueous
\(ZnCl_2\) :\(Zn^{2+}\) (aq) + 2\(e^-\) → Zn(s) \(E^0\) = -0.76 V
2\(H_2\)O (l) + 2\(e^-\) → H2 (g) + 2\(OH^-\) (aq) \(E^0\) = - 0.83 V
Which one will take place? Why?
Following reactions can occur at cathode during the electrolysis of aqueous silver nitrate solution using Pt electrodes:
Define the following terms :
(i) Fuel cell
(ii) Limiting molar conductivity
State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution ?