The conductivity of an aqueous solution of NaCl in a cell is 92 \(Ω^{−1}\) \(cm^{-1}\) the resistance offered by this cell is 247.8 Ω . Calculate the cell constant.
Specific conductivity = Cell constant/ Resistance
Cell constant = conductivity × Resistance
= 92 \(Ω^{−1}\) \(cm^{-1}\) × 247.8 Ω
= 22797.6 \(Ω^{−1}\)
Cell constant = conductivity × Resistance
= 92 \(Ω^{−1}\) \(cm^{-1}\) × 247.8 Ω
= 22797.6 \(Ω^{−1}\)
The conductivity of 0.20 M solution of KCl at 298 K is 0.025 Scm⁻¹. Calculate its molar conductivity.
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The conductivity of 0.20 M solution of KCl at 298 K is 0.025 Scm⁻¹. Calculate its molar conductivity.