State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution ?
Kohlrausch law of independent migration of ions :
The law states that limiting molar conductivity of an electrolyte can be represented by the sum of the individual contributions of the anion and cation of the electrolyte.
Λo=v+Λo++v−Λo−
On dilution, the conductivity (k) of the electrolyte decreases as the number of ions per unit volume of solution decreases.
The law states that limiting molar conductivity of an electrolyte can be represented by the sum of the individual contributions of the anion and cation of the electrolyte.
Λo=v+Λo++v−Λo−
On dilution, the conductivity (k) of the electrolyte decreases as the number of ions per unit volume of solution decreases.
The conductivity of metals decreases while that of electrolytes increases with increase in temperature. Why?
The conductivity of 0.20 M solution of KCl at 298 K is 0.025 Scm⁻¹. Calculate its molar conductivity.
The potential of a hydrogen electrode at pH = 10 is
a. 0.591 V
b. 0.00 V
c. – 0.591 V
d. -0.059 V
The electrical resistance of a column of 0.05 M KOH solution of diameter 1 cm and length 45.5 cm is 4.55 × 10³ ohm. Calculate its molar conductivity.
Explain why :
(i) E° for Mn³⁺/Mn²⁺ couple is more positive than that for Fe³⁺/Fe²⁺. (At. Nos. Mn = 25, Fe = 26).
(ii) Ce³⁺ can be easily oxidized to Ce⁴⁺. (At. No.Ce = 58).
State Raoult’s law for the solution containing volatile components. What is the similarity between Raoult’s law and Henry’s law ?
Calculate the degree of dissociation (α) of acetic acid if its molar conductivity (Λm) is 39.05 Scm² mol⁻¹. Given Λo(H⁺) = 349.6 Scm² mol⁻¹ and Λo(CH₃COO⁻) = 40.9 Scm² mol⁻¹..
Explain the solubility rule “like dissolves like” in terms of intermolecular forces that exist in solutions.
Complete and balance the following chemical equations:
(a) Fe²⁺ + MnO₄⁻ + H⁺ →
(b) MnO₄⁻ + H₂O + I⁻ →
What is meant by rate of a reaction ? Differentiate between average rate and instantaneous rate of a reaction.