Question

Consider the reaction: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -> 2Cr³⁺ + 7H₂O. What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr₂O₇²⁻?

Answer-Image

Similar Questions From Electrochemistry:

The conductivity of metals decreases while that of electrolytes increases with increase in temperature. Why?

State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution ?

Calculate pH of following half-cell. Pt, \(H_2\) / \(H_2\)\(SO_4\) , if its electrode potential is 0.03V.

Define the following terms : (i) Fuel cell (ii) Limiting molar conductivity

The conductivity of 0.20 M solution of KCl at 298 K is 0.025 Scm⁻¹. Calculate its molar conductivity.

The potential of a hydrogen electrode at pH = 10 is a. 0.591 V b. 0.00 V c. – 0.591 V d. -0.059 V

Define the following terms : (i) Molar conductivity (), (ii) Secondary batteries.

More 3 Marks Questions:

Calculate the molar conductivity and degree of dissociation. Conductivity of 2.5 × 10⁻⁴M methanoic acid is 5.25 × 10⁻⁵ Scm⁻¹. Given : = 50.5Scm² mol⁻¹

Calculate emf of the following cell Cd/\(Cd^{2+}\) (.10 M)//\(H_+\) (.20 M)/\(H_2\) (0.5 atm)/Pt [Given E° for \(Cd^{2+}\) /Cd = -0.403V]

(i) Account for the following : (a) Cu⁺ is unstable in an aqueous solution. (b) Transition metals form complex compounds. (ii) Complete the following equation : CrO₂₇²⁻ + 8H⁺ + 3NO₂⁻ →

The vapour pressure of pure liquids A and B at 400 K are 450 and 700 mm Hg respectively. Find out the composition of liquid mixture if total pressure at this temperature is 600 mm Hg.

Consider the reaction: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -> 2Cr³⁺ + 7H₂O. What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr₂O₇²⁻?

(a) Calculate G° for the reaction Zn(s) + \(Cu^{2+}\)(aq) → \(Zn^{2+}\)(aq) + Cu(s) Given: E° for \(Zn^{2+}\)/Zn = -0.76V and E° for \(Cu^{2+}\)/Cu = +0.34 V R = 8.314 \(JK^{–1}\) \(mol^{–1}\), F = 96500 \(mol^{–1}\)

Consider the standard electrode potential values (M²⁺/M) of the elements of the first transition series.

Scroll to Top