If A and B are two independent events, then prove that the probability of occurrence of at least one of A and B is given by 1 – P(A’) · P(B’)
Required probability = P(A U B)
= P(A) + P(B) – P(A) · P(B)
= P(A) [1 – P(B)] + 1 – P(B’)
= P(A) P(B’) – P(B’) + 1
= (1 – P(B’) (1 – P(A))
= 1 – P(A’) P(B’)
= P(A) + P(B) – P(A) · P(B)
= P(A) [1 – P(B)] + 1 – P(B’)
= P(A) P(B’) – P(B’) + 1
= (1 – P(B’) (1 – P(A))
= 1 – P(A’) P(B’)
If A and B are two independent events such that P(A' ∩ B)= 2/15 and P(A ∩ B')= 1/6, then find P(A) and P(B).
If E and F are independent events, then show that
(i) E and F' are independent events.
(ii) E' and F are also independent events.
If A and B are two events such that P(A) = 0.4, P(B) = 0.8 and P(B/A) = 0.6, then find P(A/B).
If A and B are events such that P(A|B) = P(B|A), then
(a) A ⊂ B but A ≠ B
(b) A = B
(c) A ∩ B = Φ
(d) P(A) = P(B)
If E and F are two events such that P(E) = 1/4, P(F) = 1/2 and P(E ∩ F) = 1/8, find
(i) P(E or F)
(ii) P(not E and not F).
If E and F be two events such that P(E) = 1/3, P(F) = 1/4, find P(E U F) if E and F are independent events.
Obtain the differential equation of the family of circles passing through the points (a, 0) and (– a, 0).
The total revenue received from the sale of x units of a product is given by R(x) = 3x² + 36x + 5 in rupees. Find the marginal revenue when x = 5, where by marginal revenue we mean the rate of change of total revenue with respect to the number of items sold at an instant.
Find the differential equation of the family of curves y²= 4ax.
If P(A) = 0.4, P(B) = p, P(A U B) = 0.6 and A and B are given to the independent events, find the value of ‘p’.