Question

Highest oxidation state of manganese in fluoride is +4 (MnF₄) but highest oxidation state in oxides is +7 (Mn₂O₇) because

(a) fluorine is more electronegative than oxygen.
(b) fluorine does not possess d-orbitals.
(c) fluorine stabilises lower oxidation state.
(d) in covalent compounds fluorine can formsingle bond only while oxygen forms double bond.
(d) in covalent compounds fluorine can form single bond only while oxygen forms double bond.

Similar Questions From D And F Block Elements:

Give reasons : (i) Mn shows the highest oxidation state of +7 with oxygen but with fluorine it shows the highest oxidation state of +4. (ii) Transition metals show variable oxidation states. (iii) Actinoids show irregularities in their electronic configurations.

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More MCQ Questions:

Highest oxidation state of manganese in fluoride is +4 (MnF₄) but highest oxidation state in oxides is +7 (Mn₂O₇) because (a) fluorine is more electronegative than oxygen. (b) fluorine does not possess d-orbitals. (c) fluorine stabilises lower oxidation state. (d) in covalent compounds fluorine can formsingle bond only while oxygen forms double bond.

Which of the following statements is not true about amorphous solids? (A) On heating they may become crystalline at certain temperature. (B) They may become crystalline on keeping for long time. (C) Amorphous solids can be moulded by heating. (D) They are anisotropic in nature.

Which of the following alcohols gives 2-butenc on dehydration by conc.\(H_2\)\(SO_4\)? (a) 2-methyl propene-2-ol. (b) 2-methyl 1 -propanol. (c) Butane-2-ol. (d) Butane 1-ol.

What would be the reactant and reagent used to obtain 2, 4-dimenthyl pentan-3-ol? (a) Propanal and propyl magnesium bromide. (b) 3-methylbutanal and 2-methyl magnesium iodide. (c) 2-dimethylpropanone and methyl magnesium iodide. (d) 2-methylpropanal and isopropyl magnesium iodide.

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