The ratio of intensities at minima to the maxima in young’s double slit experiment is 9 : 25. Find the ratio of the widths of two slits.
(A) 16: 1
(B) 1: 16
(C) 4 : 1
(D) 1 : 4
(A) 16: 1
(B) 1: 16
(C) 4 : 1
(D) 1 : 4
(A) 16: 1
Ratio of intensities of two waves are given by 4 :1. Then the ratio of the amplitudes of the two waves.
(a) 2 : 1
(b) 1 : 2
(c) 4 : 1
(d) 1 : 4
Two slits in Young’s double slit experiment have widths in the ratio 81:1. The ratio of the amplitudes of light waves is
(a) 3 :1
(b) 3 : 2
(c) 9 :1
(d) 6:1
Two waves having intensities in the ratio of 9:1 produce interference. The ratio of the maximum to the minimum intensity is
I. 9:1
II. 4:1
III. 1:2
IV. 1:3
Two interfering beams have intensities in the ratio of 9:4. Then the ratio of maximum to minimum intensity in the interference pattern is
(A) 25:1
(B) 13:5
(C) 5:1
(D) 3:2
The light sources used in Young’s double slit experiment are:
(A) Incoherent
(B) Coherent
(C) White light
(D) Blue-green-red Light.
In the Young double slit experiment, the fringe pattern as seen on the screen is:
(A) Parabola
(B) Hyperbola
(C) Ellipse
(D) Spiral
In an interference experiment, the spacing between successive maxima and minima is
(A) λd / D
(B) λD / d
(C) dD / λ
(D) λd / 4D
A parallel plate air capacitor has a capacitance 18μF. If the distance between the plates is tripled and a dielectric medium is introduced, the capacitance becomes 72μF. The dielectric constant of the medium is
(a) 4
(b) 9
(c) 12
(d) 2
In electric arc furnace Cu or Iron is melted due to variation of
(a) current
(b) magnetic field
(c) voltage
(d) electric field
Two coherent monochromatic light beams of intensities I and 41 superimpose. The maximum and minimum possible intensities in the resulting beam are:
(a) 5I and I
(b) 5I and 3I
(c) 3I and I
(d) 9I and I
Five resistances are combined according to the figure. The equivalent resistances between the points X and Y will be
(a) 10 Ω
(b) 22 Ω
(c) 20 Ω
(d) 50 Ω
Let \(ε_0\) denote the dimensional formula of the permittivity of vacuum. If M=mass, L=length, T=time and
I=electric current, then
(A) [M⁻¹L⁻³T²I]
(B) [M⁻¹L⁻³T⁴I²]
(C) [M⁻¹L²T⁻¹I⁻²]
(D) [M⁻¹L²T⁻¹I]
In the Young’s double slit experiment both the slits are similar. If the length of one of the slits is halved, which of the following is true?
(a) Bright fringes become narrower.
(b) Bright fringes become wider.
(c) Dark fringes become darker
(d) Dark fringes become brighter.
A Daniel cell is balanced on 125 cm length of a potentiometer wire. When the cell is short circuited with a 2 Ω resistance, the balancing length obtained is 100 cm. Internal resistance of the cell will be
(a) 1.5 Ω
(b) 0.5 Ω
(c) 1.25 Ω
(d) 4/5 Ω